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7x^2+53x-90=0
a = 7; b = 53; c = -90;
Δ = b2-4ac
Δ = 532-4·7·(-90)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-73}{2*7}=\frac{-126}{14} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+73}{2*7}=\frac{20}{14} =1+3/7 $
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